1. **State the problem:** We are given probabilities of plots having pairs and all three types of trees: cedar, cypress, and redwood. We want to find the probability that a randomly selected plot has exactly two of these three types. 2. **Given data:** - $P(C \cap Cy) = 0.40$ (cedar and cypress) - $P(C \cap R) = 0.25$ (cedar and redwood) - $P(Cy \cap R) = 0.20$ (cypress and redwood) - $P(C \cap Cy \cap R) = 0.15$ (all three) 3. **Formula and explanation:** The probability of exactly two types means the plot has any two types but not the third. We use the formula: $$ P(\text{exactly two}) = P(C \cap Cy) + P(C \cap R) + P(Cy \cap R) - 3 \times P(C \cap Cy \cap R) $$ This is because the triple intersection is included in each pair intersection, so we subtract it three times to remove overcounting. 4. **Calculate:** $$ P(\text{exactly two}) = 0.40 + 0.25 + 0.20 - 3 \times 0.15 $$ $$ = 0.85 - 0.45 $$ $$ = 0.40 $$ 5. **Interpretation:** The probability that a randomly selected plot has exactly two of the three types of trees is 0.40 or 40%.