1. **Stating the problem:** We are given percentages of students in various faculties and asked to find probabilities related to faculty membership. 2. **Recall:** Probability of an event = (Percentage of that event) / 100. 3. **Given data:** - Social Sciences = 40.86% - Sport = 0.58% - Gender & Development Studies = 0.49% - Engineering = 1.74% 4. **a) Probability student is in Social Sciences:** $$P(\text{Social Sciences}) = \frac{40.86}{100} = 0.4086$$ 5. **b) Probability student is in Sport, Gender & Development Studies, or Engineering:** Sum the percentages: $$0.58 + 0.49 + 1.74 = 2.81$$ Convert to probability: $$P(\text{Sport or Gender & Development Studies or Engineering}) = \frac{2.81}{100} = 0.0281$$ 6. **c) Probability student is NOT in Social Sciences:** $$P(\text{Not Social Sciences}) = 1 - P(\text{Social Sciences}) = 1 - 0.4086 = 0.5914$$ **Final answers:** - a) 0.4086 - b) 0.0281 - c) 0.5914