1. **State the problem:** We want to find the probability that the last card dealt from a shuffled deck of 52 cards, after dealing 13 cards, is an ace.
2. **Understand the scenario:** There are 4 aces in a deck of 52 cards.
3. **Key insight:** Since the deck is shuffled, every card is equally likely to be in any position.
4. **Probability formula:** The probability that a specific card (like an ace) is in a specific position is the number of favorable outcomes divided by the total number of outcomes.
5. **Calculate probability:** The probability that the last card dealt (the 13th card) is an ace is the number of aces divided by the total number of cards:
$$\text{Probability} = \frac{4}{52} = \frac{1}{13}$$
6. **Explanation:** Because the deck is well shuffled, the position of each card is random and equally likely. So the chance that the last card is an ace is simply the fraction of aces in the deck.
**Final answer:**
$$\boxed{\frac{1}{13}}$$
Last Card Ace F7B795
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