1. **State the problem:** Peyton draws two marbles from a bag containing one red, one blue, and one green marble. Each time, the marble is returned to the bag before the next draw. We want to find how many different outcomes are possible when drawing two marbles this way. 2. **Understand the process:** Since Peyton returns the marble after the first draw, the draws are independent, and the same marble can be drawn twice. 3. **Formula used:** The number of possible outcomes when drawing with replacement is given by: $$\text{Number of outcomes} = n^k$$ where $n$ is the number of possible outcomes per draw, and $k$ is the number of draws. 4. **Apply the formula:** Here, $n=3$ (red, blue, green) and $k=2$ (two draws), so: $$\text{Number of outcomes} = 3^2$$ 5. **Calculate:** $$3^2 = 3 \times 3 = 9$$ 6. **Interpretation:** There are 9 possible outcomes when Peyton draws two marbles with replacement from the bag. **Final answer:** $$\boxed{9}$$