1. The problem asks for the experimental probability that Tina will miss two free throws in a row. 2. Experimental probability is calculated by dividing the frequency of the desired outcome by the total number of trials. 3. From the table, the frequency of "miss, miss" is 10. 4. Calculate the total number of trials by summing all frequencies: $$10 + 8 + 4 + 3 = 25$$ 5. The experimental probability is: $$\frac{10}{25}$$ 6. Show the cancellation of common factors: $$\frac{\cancel{10}}{\cancel{25}} = \frac{2}{5}$$ 7. Convert the fraction to a decimal: $$\frac{2}{5} = 0.4$$ 8. Therefore, the experimental probability that Tina will miss two free throws in a row is 0.4.