1. **State the problem:** We have a bag with 12 red, 6 blue, 8 green, and 14 brown M&Ms. We draw one M&M 60 times with replacement. We want to predict how many times a red or blue M&M will be drawn. 2. **Calculate total M&Ms:** Total = 12 + 6 + 8 + 14 = 40. 3. **Calculate probability of drawing red or blue:** $$P(\text{red or blue}) = \frac{12 + 6}{40} = \frac{18}{40} = \frac{9}{20}$$ 4. **Use expected value formula:** Expected number of red or blue draws = Total draws $\times$ Probability $$= 60 \times \frac{9}{20}$$ 5. **Simplify:** $$60 \times \frac{9}{20} = \cancel{60}^3 \times \frac{9}{\cancel{20}^\frac{2}{3}} = 3 \times 9 = 27$$ 6. **Conclusion:** A reasonable prediction is 27 times. **Answer: C) 27**