1. **Problem Statement:** We have a box with 5 red and 3 white balls (total 8 balls). Two balls are drawn in succession. (A) Find the probability that the second ball is red given the first ball was replaced before the second draw. 2. **Key Concept:** When the first ball is replaced, the total number of balls remains the same for the second draw. 3. **Formula:** The probability of an event is given by $$P(E) = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}$$ 4. **Step-by-step solution:** - Since the first ball is replaced, the composition of the box remains 5 red and 3 white balls for the second draw. - The probability that the second ball is red is therefore $$P(\text{second red}) = \frac{5}{8}$$ 5. **Final answer:** $$\boxed{\frac{5}{8}}$$