1. **State the problem:** Given probabilities $P(A \cup B) = 0.84$, $P(A \cap B) = 0.12$, and $P(A) = 0.60$, find $P(B)$. 2. **Formula used:** The formula for the union of two events is: $$P(A \cup B) = P(A) + P(B) - P(A \cap B)$$ This formula accounts for the overlap between $A$ and $B$ to avoid double counting. 3. **Substitute known values:** $$0.84 = 0.60 + P(B) - 0.12$$ 4. **Simplify the equation:** $$0.84 = 0.48 + P(B)$$ 5. **Isolate $P(B)$:** $$P(B) = 0.84 - 0.48$$ 6. **Calculate the result:** $$P(B) = 0.36$$ **Final answer:** $$\boxed{P(B) = 0.36}$$