1. **State the problem:** We need to order the bags A, B, and C by their probabilities of picking a green counter from lowest to highest. 2. **Given probabilities:** - Bag A: $P(\text{green}) = \frac{4}{5}$ - Bag B: $P(\text{green}) = \frac{11}{15}$ - Bag C: $P(\text{green}) = \frac{7}{10}$ 3. **Convert all probabilities to decimals for easy comparison:** - Bag A: $\frac{4}{5} = 0.8$ - Bag B: $\frac{11}{15} \approx 0.7333$ - Bag C: $\frac{7}{10} = 0.7$ 4. **Order the decimals from lowest to highest:** $$0.7 < 0.7333 < 0.8$$ 5. **Match back to bags:** - Lowest: Bag C ($0.7$) - Middle: Bag B ($0.7333$) - Highest: Bag A ($0.8$) **Final answer:** The order from lowest to highest probability is **Bag C, Bag B, Bag A**.