1. **State the problem:** We are given three probabilities of winning three different games: 0.41, 38%, and 4/10. We need to order these probabilities from least likely to most likely. 2. **Convert all probabilities to a common format:** - 0.41 is already a decimal. - 38% means 38 out of 100, so as a decimal it is $\frac{38}{100} = 0.38$. - 4/10 as a decimal is $\frac{4}{10} = 0.4$. 3. **Compare the decimal values:** - 0.38 - 0.4 - 0.41 4. **Order from least to most likely:** $$0.38 < 0.4 < 0.41$$ 5. **Final answer:** The order of probabilities from least likely to most likely is 38%, 4/10, 0.41.