1. **Problem (a):** Find the probability of picking a pencil that is red or yellow. 2. The probability of picking a pencil of each colour is given as: - Red: $0.35$ - Yellow: $0.25$ - Blue: $0.1$ - Green: Unknown 3. The sum of all probabilities must equal 1 because one of the colours must be picked: $$0.35 + 0.25 + 0.1 + P(\text{Green}) = 1$$ 4. Calculate the probability of green: $$P(\text{Green}) = 1 - (0.35 + 0.25 + 0.1) = 1 - 0.7 = 0.3$$ 5. To find the probability of picking a pencil that is red or yellow, add their probabilities: $$P(\text{Red or Yellow}) = P(\text{Red}) + P(\text{Yellow}) = 0.35 + 0.25 = 0.6$$ 6. **Answer (a):** The probability of picking a red or yellow pencil is $0.6$. --- 7. **Problem (b):** Complete the table with the missing probability for green pencils. 8. From step 4, we found $P(\text{Green}) = 0.3$. 9. **Answer (b):** The completed table is: | Red | Yellow | Blue | Green | |------|---------|-------|--------| | 0.35 | 0.25 | 0.1 | 0.3 | --- 10. **Second problem:** Find the probability of not picking a blue counter. 11. Given probabilities: - Red: $0.05$ - Green: $0.3$ - Blue: $0.65$ 12. The probability of not picking a blue counter is the sum of probabilities of red and green counters: $$P(\text{Not Blue}) = P(\text{Red}) + P(\text{Green}) = 0.05 + 0.3 = 0.35$$ 13. **Answer:** The probability of not picking a blue counter is $0.35$.