1. **Problem statement:**
Find the probability that an integer chosen between 70 and 100 is (i) a prime number, (ii) divisible by 7.
2. **Total numbers between 70 and 100:**
These are integers from 71 to 99 inclusive.
Number of integers = $99 - 71 + 1 = 29$.
3. **(i) Probability of choosing a prime number:**
List prime numbers between 71 and 99:
71, 73, 79, 83, 89, 97
Count = 6 primes.
Probability = $\frac{\text{number of primes}}{\text{total numbers}} = \frac{6}{29}$.
4. **(ii) Probability of choosing a number divisible by 7:**
Find multiples of 7 between 71 and 99:
$7 \times 11 = 77$, $7 \times 12 = 84$, $7 \times 13 = 91$, $7 \times 14 = 98$
Count = 4 numbers.
Probability = $\frac{4}{29}$.
**Final answers:**
(i) Probability prime = $\frac{6}{29}$
(ii) Probability divisible by 7 = $\frac{4}{29}$
Probability Prime Divisible C2A416
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