1. **State the problem:** We want to find the probability of drawing three red marbles in a row from the bag described. 2. **Count total marbles:** The bag has 4 rows and 4 columns, so total marbles = $4 \times 4 = 16$. 3. **Count red marbles:** From the description: - Row 3 has 1 red marble. - Row 4 has 1 red marble. Total red marbles = 2. 4. **Probability formula:** When drawing without replacement, the probability of drawing 3 red marbles in a row is: $$P(\text{3 Red}) = \frac{\text{#Red}_1}{\text{Total}_1} \times \frac{\text{#Red}_2}{\text{Total}_2} \times \frac{\text{#Red}_3}{\text{Total}_3}$$ where $\text{#Red}_i$ and $\text{Total}_i$ are the number of red marbles and total marbles remaining at draw $i$. 5. **Evaluate:** Since there are only 2 red marbles, drawing 3 red marbles is impossible. 6. **Conclusion:** $$P(\text{3 Red}) = 0.000$$ The probability of drawing three red marbles in a row is zero because there are only two red marbles in the bag.