1. **State the problem:** We have a bag with 2 red marbles and 3 blue marbles, total 5 marbles. We want to find the probability of drawing 2 red marbles when drawing 2 marbles without replacement. 2. **Formula for probability:** $$\text{Probability} = \frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}}$$ 3. **Calculate total number of ways to draw 2 marbles from 5:** $$\binom{5}{2} = \frac{5!}{2!(5-2)!} = \frac{5 \times 4}{2 \times 1} = 10$$ 4. **Calculate number of favorable outcomes (drawing 2 red marbles):** There are 2 red marbles, so number of ways to choose 2 red marbles: $$\binom{2}{2} = 1$$ 5. **Calculate probability:** $$\text{Probability} = \frac{1}{10}$$ 6. **Final answer:** The probability of drawing the two red marbles is **$\frac{1}{10}$** or 0.1.