1. **Stating the problem:** Stephen and Fiona performed 50 draws from a deck of cards with replacement. The number of times Fiona chose each picture card is given: King = 8, Queen = 3, Jack = 4. We need to find: (i) Number of times a non-picture card was chosen. (ii) Relative frequency of getting a King. (iii) Relative frequency of getting a King or a Jack. (iv) Relative frequency of not getting a picture card. 2. **Formula and rules:** - Relative frequency = \frac{\text{Number of times event occurs}}{\text{Total number of trials}}. - Simplify fractions by dividing numerator and denominator by their greatest common divisor. 3. **Calculations:** (i) Total picture cards chosen = 8 + 3 + 4 = 15. Number of times non-picture card chosen = Total draws - picture cards chosen = 50 - 15 = 35. (ii) Relative frequency of King = \frac{8}{50}. Simplify by dividing numerator and denominator by 2: $$\frac{\cancel{8}^4}{\cancel{50}^{25}} = \frac{4}{25}$$ (iii) Relative frequency of King or Jack = \frac{8 + 4}{50} = \frac{12}{50}. Simplify by dividing numerator and denominator by 2: $$\frac{\cancel{12}^6}{\cancel{50}^{25}} = \frac{6}{25}$$ (iv) Relative frequency of not getting a picture card = \frac{35}{50}. Simplify by dividing numerator and denominator by 5: $$\frac{\cancel{35}^7}{\cancel{50}^{10}} = \frac{7}{10}$$ 4. **Final answers:** (i) 35 times. (ii) Relative frequency of King = $\frac{4}{25}$. (iii) Relative frequency of King or Jack = $\frac{6}{25}$. (iv) Relative frequency of not getting a picture card = $\frac{7}{10}$. These fractions represent the simplest form of the relative frequencies based on the experiment.