Subjects probability

Spinner Coloring A0D60C

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1. **Problem statement:** We need to color a spinner (Glücksrad) divided into 12 equal segments according to the given probabilities: - $P(\text{orange}) = \frac{1}{3}$ - $P(\text{blue}) = \frac{1}{4}$ - $P(\text{green}) = \frac{1}{4}$ - $P(\text{light blue}) = \frac{1}{6}$ 2. **Formula and rules:** The probability of each color corresponds to the fraction of the 12 segments that should be colored in that color. Since the spinner has 12 segments, the number of segments for each color is: $$\text{Number of segments} = P(\text{color}) \times 12$$ 3. **Calculate segments for each color:** - Orange: $$\frac{1}{3} \times 12 = 4$$ segments - Blue: $$\frac{1}{4} \times 12 = 3$$ segments - Green: $$\frac{1}{4} \times 12 = 3$$ segments - Light blue: $$\frac{1}{6} \times 12 = 2$$ segments 4. **Check total segments:** $$4 + 3 + 3 + 2 = 12$$ segments, which matches the total number of segments. 5. **Conclusion:** Color the spinner with 4 orange segments, 3 blue segments, 3 green segments, and 2 light blue segments to match the given probabilities exactly.