1. **Stating the problem:** We have a spinner divided into six equal sections labeled 4, 1, 1, 2, 3, 1. Seven players spin the spinner and their outcomes are recorded. 2. **Understanding the spinner:** Since the spinner is divided into six equal sections, each section has a probability of $\frac{1}{6}$ of being landed on. 3. **Labels and outcomes:** The labels on the spinner are 4, 1, 1, 2, 3, 1. Notice that the number 1 appears three times, 4 appears once, 2 once, and 3 once. 4. **Calculating probabilities of each outcome:** - Probability of landing on 1: $\frac{3}{6} = \frac{1}{2}$ - Probability of landing on 4: $\frac{1}{6}$ - Probability of landing on 2: $\frac{1}{6}$ - Probability of landing on 3: $\frac{1}{6}$ 5. **Player outcomes:** - Anna: 1 - John: 4 - Carrie: 4 - Steve: 1 - Ethan: 2 - Liz: 4 - Jane: 1 6. **Summary:** The spinner's sections and player outcomes are consistent with the probabilities calculated. No further calculations requested.