1. **State the problem:** We want to find the probability that the player gets a strike on the second throw, given that they did not get a strike on the first throw. 2. **Given data:** - Probability of strike on first throw: $P(S_1) = 0.45$ - Probability of no strike on first throw: $P(\neg S_1) = 1 - 0.45 = 0.55$ - Probability of strike on second throw given no strike on first: $P(S_2 | \neg S_1) = 0.30$ 3. **Formula used:** The probability of getting a strike on the second throw is the probability that the first throw was not a strike and the second throw is a strike: $$P(S_2) = P(\neg S_1) \times P(S_2 | \neg S_1)$$ 4. **Calculate:** $$P(S_2) = 0.55 \times 0.30$$ 5. **Intermediate step with cancellation:** $$P(S_2) = \cancel{0.55} \times \cancel{0.30}$$ 6. **Final calculation:** $$P(S_2) = 0.165$$ 7. **Interpretation:** The probability that the player gets a strike on the second throw (after missing the first) is 0.165 or 16.5%.