1. The problem asks for the probability that a student plays a musical instrument and the probability that a student is a junior who does not play a musical instrument. 2. Probability is calculated as the number of favorable outcomes divided by the total number of outcomes. 3. For part (i), the probability that a student plays a musical instrument is given as 36%, which means: $$P(\text{plays instrument}) = 0.36$$ 4. For part (ii), the probability that a student is a junior who does not play a musical instrument is given as a fraction $\frac{1.16}{3}$ and also as $\frac{6}{10}$. We need to clarify and simplify these. 5. Simplify $\frac{1.16}{3}$: $$\frac{1.16}{3} \approx 0.3867$$ 6. The fraction $\frac{6}{10}$ simplifies to: $$\frac{6}{10} = \frac{\cancel{6}}{\cancel{10}} = \frac{3}{5} = 0.6$$ 7. Since the two values differ, the correct probability for juniors who do not play an instrument is likely $\frac{6}{10} = 0.6$ or 60%. 8. Therefore, the answers are: (i) Probability student plays a musical instrument = 36% or 0.36 (ii) Probability student is a junior who does not play a musical instrument = 60% or 0.6 Final answers: - $P(\text{plays instrument}) = 0.36$ - $P(\text{junior and no instrument}) = 0.6$