1. **State the problem:** We have a critical airline component with a failure probability of $0.0058$. The system uses triple modular redundancy, meaning there are three independent components working together.
2. **Formulas and rules:**
- The probability all three components fail (disaster) is the product of their individual failure probabilities because failures are independent:
$$P(\text{all fail}) = p^3$$
- The probability at least one component does not fail is the complement of all failing:
$$P(\text{at least one works}) = 1 - P(\text{all fail})$$
3. **Calculate the probability all three fail:**
$$P(\text{all fail}) = (0.0058)^3 = 0.0058 \times 0.0058 \times 0.0058$$
Calculate stepwise:
$$0.0058 \times 0.0058 = 0.00003364$$
$$0.00003364 \times 0.0058 = 0.000000195112$$
So,
$$P(\text{all fail}) = 0.000000195112$$
4. **Calculate the probability at least one does not fail:**
$$P(\text{at least one works}) = 1 - 0.000000195112 = 0.999999804888$$
5. **Final answers:**
- Probability all three fail (disaster): $0.0000001951$ (approximately)
- Probability at least one does not fail: $0.9999998$ (approximately)
These results show that triple modular redundancy greatly reduces the chance of total failure.
Triple Modular Redundancy 21Ffc5
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