1. **State the problem:** We are given probabilities for paperback books, non-fiction books, and books that are both paperback and non-fiction. We need to find the probability of selecting a book that is neither paperback nor non-fiction. 2. **Given:** - $P(\text{paperback}) = 0.44$ - $P(\text{non-fiction}) = 0.26$ - $P(\text{paperback} \cap \text{non-fiction}) = 0.19$ 3. **Formula used:** The probability of the union of two events is: $$P(A \cup B) = P(A) + P(B) - P(A \cap B)$$ 4. **Calculate $P(\text{paperback} \cup \text{non-fiction})$:** $$P(\text{paperback} \cup \text{non-fiction}) = 0.44 + 0.26 - 0.19 = 0.51$$ 5. **Find $P(\text{neither paperback nor non-fiction})$:** This is the complement of the union: $$P(\text{neither}) = 1 - P(\text{paperback} \cup \text{non-fiction}) = 1 - 0.51 = 0.49$$ 6. **Answer:** $$\boxed{0.49}$$ This means there is a 0.49 probability that a randomly chosen book is neither paperback nor non-fiction.