1. **State the problem:** We want to find the probability that at least two out of three randomly selected people share the same Chinese zodiac sign. 2. **Total zodiac signs:** There are 12 zodiac signs. 3. **Approach:** It's easier to find the complement probability that all three people have different zodiac signs, then subtract from 1. 4. **Calculate the complement probability:** - The first person can have any of the 12 signs: probability = $\frac{12}{12} = 1$ - The second person must have a different sign: probability = $\frac{11}{12}$ - The third person must have a different sign from the first two: probability = $\frac{10}{12}$ So, the probability all three have different signs is: $$ 1 \times \frac{11}{12} \times \frac{10}{12} = \frac{110}{144} $$ 5. **Simplify the fraction:** $$ \frac{110}{144} = \frac{\cancel{110}}{\cancel{144}} \text{ (dividing numerator and denominator by 2)} = \frac{55}{72} $$ 6. **Find the desired probability:** $$ P(\text{at least two share the same sign}) = 1 - P(\text{all different}) = 1 - \frac{55}{72} = \frac{72}{72} - \frac{55}{72} = \frac{17}{72} $$ **Final answer:** $\boxed{\frac{17}{72}}$ This corresponds to option A.