1. The problem is to estimate the earthwork quantities and costs for the proposed two-storey residential unit based on the provided data for member C1/F1. 2. The formula for total cut and fill volumes is: $$\text{Total Cut} = \text{Unit Quantity} \times \text{Cut per unit}$$ $$\text{Total Fill} = \text{Unit Quantity} \times \text{Fill per unit}$$ Shrinkage is accounted as 10% of total fill: $$\text{Shrinkage} = 0.10 \times \text{Total Fill}$$ Total shrunken fill is: $$\text{Total Shrunken Fill} = \text{Total Fill} - \text{Shrinkage}$$ 3. Given for C1/F1: Unit Quantity = 6 pcs Cut per unit = 10 m³ Fill per unit = 7 m³ 4. Calculate total cut: $$6 \times 10 = 60\, m^3$$ 5. Calculate total fill: $$6 \times 7 = 42\, m^3$$ 6. Calculate shrinkage (10% of total fill): $$0.10 \times 42 = 4.2\, m^3$$ 7. Calculate total shrunken fill: $$42 - 4.2 = 37.8\, m^3$$ 8. Extra soil needed is 0 m³ as given. 9. Labor and equipment costs are calculated by multiplying volume by rate 320 per m³: Total cut cost: $$60 \times 320 = 19200$$ Total fill cost: $$42 \times 320 = 13440$$ Extra soil cost is 0. 10. Summary: - Total Cut = 60 m³ - Total Fill = 42 m³ - Shrinkage = 4.2 m³ - Total Shrunken Fill = 37.8 m³ - Extra Soil Needed = 0 m³ - Labor and Equipment Costs: Cut = 19200, Fill = 13440, Extra Soil = 0 This estimation method can be applied similarly to other members once their data is available.