1. The problem asks to build a diagram showing the ratio of silver medals to all medals. 2. First, find the total number of medals: 5 gold + 2 silver + 1 bronze = 8 medals. 3. The ratio of silver medals to all medals is $ \frac{2}{8} $. 4. Simplify the ratio by dividing numerator and denominator by their greatest common divisor 2: $$\frac{\cancel{2}}{\cancel{8}} = \frac{1}{4}$$ 5. This means for every 4 medals, 1 is silver. 6. To build the diagram, represent the ratio as two groups: one group for silver medals and one for the other medals. 7. Since the ratio is 1:4, the silver medals group is 1 part and the other medals group is 3 parts (because total parts = 4, and silver is 1 part, so others = 4 - 1 = 3 parts). 8. Therefore, the diagram should have 1 box labeled '1' for silver medals and 3 boxes labeled '3' for other medals, or equivalently two boxes with labels '1' and '3' respectively. Final answer: The ratio of silver medals to all medals is $ \frac{1}{4} $, so the diagram should show 1 part silver medals and 3 parts other medals.