1. The problem is to find the shaded area above $z=1.46$ on the standard normal curve. 2. The standard normal distribution has mean $0$ and standard deviation $1$. 3. The area above $z=1.46$ corresponds to the probability $P(Z > 1.46)$. 4. We use the cumulative distribution function (CDF) $\Phi(z)$ which gives $P(Z \leq z)$. 5. The shaded area above $z=1.46$ is $1 - \Phi(1.46)$. 6. From standard normal tables or a calculator, $\Phi(1.46) \approx 0.9279$. 7. Therefore, the shaded area is $$1 - 0.9279 = 0.0721.$$ 8. This means about 7.21% of the data lies above $z=1.46$ on the standard normal curve.