1. **Problem statement:** Find the area to the left of $z = -1.15$ or to the right of $z = 1.68$ in the standard normal distribution. 2. **Formula and rules:** The total area under the standard normal curve is 1. - Area to the left of $z$ is $P(Z < z)$. - Area to the right of $z$ is $P(Z > z) = 1 - P(Z < z)$. - For "or" events, if the events are mutually exclusive, sum the areas. 3. **Find individual areas:** - $P(Z < -1.15)$ from standard normal tables or calculator is approximately 0.1251. - $P(Z > 1.68) = 1 - P(Z < 1.68)$. - $P(Z < 1.68)$ is approximately 0.9535. - So, $P(Z > 1.68) = 1 - 0.9535 = 0.0465$. 4. **Calculate total area:** $$ \text{Area} = P(Z < -1.15) + P(Z > 1.68) = 0.1251 + 0.0465 = 0.1716 $$ 5. **Interpretation:** The combined area to the left of $-1.15$ or to the right of $1.68$ is approximately 0.1716, meaning about 17.16% of the distribution lies in these tails.