1. **Stating the problem:** We are given a frequency table showing the lengths of babies born on one day at a hospital, and we want to analyze the data.
2. **Frequency table:**
Length (inches): 17, 18, 19, 20, 21
Tally counts: 1, 4, 7, 2, 2
3. **Calculate the total number of babies:**
$$1 + 4 + 7 + 2 + 2 = 16$$
4. **Calculate the mean length:**
$$\text{Mean} = \frac{17 \times 1 + 18 \times 4 + 19 \times 7 + 20 \times 2 + 21 \times 2}{16}$$
$$= \frac{17 + 72 + 133 + 40 + 42}{16} = \frac{304}{16} = 19$$
5. **Find the median length:**
Since there are 16 data points, the median is the average of the 8th and 9th values when data is ordered.
Counting the data points in order:
- 1 baby at 17 inches (positions 1)
- 4 babies at 18 inches (positions 2 to 5)
- 7 babies at 19 inches (positions 6 to 12)
The 8th and 9th babies fall in the 19-inch group.
Therefore, median = 19 inches.
6. **Compare mean and median:**
Mean = 19, Median = 19, so they are equal.
7. **Conclusion:**
The mean and median lengths are equal in this data set.
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**Summary:**
- Mean length = 19 inches
- Median length = 19 inches
- Mean equals median in this data
Baby Lengths 50A3A0
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