1. **State the problem:** Calculate the variance of the BMI measurements for the 10 individuals given. 2. **Recall the formula for sample variance:** $$s^2 = \frac{1}{n-1} \sum_{i=1}^n (x_i - \bar{x})^2$$ where $n$ is the sample size, $x_i$ are the individual BMI values, and $\bar{x}$ is the sample mean. 3. **List the BMI values:** $$30.5, 34.6, 21.5, 34.9, 22.9, 31.6, 32.7, 20.7, 28.2, 22.6$$ 4. **Calculate the mean BMI:** $$\bar{x} = \frac{30.5 + 34.6 + 21.5 + 34.9 + 22.9 + 31.6 + 32.7 + 20.7 + 28.2 + 22.6}{10}$$ $$= \frac{280.2}{10} = 28.02$$ 5. **Calculate each squared deviation:** $$ (30.5 - 28.02)^2 = 6.1504$$ $$ (34.6 - 28.02)^2 = 43.2964$$ $$ (21.5 - 28.02)^2 = 42.8164$$ $$ (34.9 - 28.02)^2 = 47.6164$$ $$ (22.9 - 28.02)^2 = 26.3044$$ $$ (31.6 - 28.02)^2 = 12.7364$$ $$ (32.7 - 28.02)^2 = 21.8884$$ $$ (20.7 - 28.02)^2 = 53.4244$$ $$ (28.2 - 28.02)^2 = 0.0324$$ $$ (22.6 - 28.02)^2 = 29.3764$$ 6. **Sum the squared deviations:** $$6.1504 + 43.2964 + 42.8164 + 47.6164 + 26.3044 + 12.7364 + 21.8884 + 53.4244 + 0.0324 + 29.3764 = 283.6426$$ 7. **Calculate the sample variance:** $$s^2 = \frac{283.6426}{10 - 1} = \frac{283.6426}{9} = 31.51696$$ 8. **Round to two decimals:** $$\boxed{31.52}$$ Thus, the variance of the BMI measurements is 31.52.