1. **Problem Statement:** We have a sample of 15 waiting times in minutes: 1.38, 2.34, 3.02, 3.20, 3.54, 3.79, 4.21, 4.50, 4.77, 5, 5.13, 5.35, 5.55, 6.10, 6.19. We need to construct a box plot and interpret it.
2. **Step 1: Order the data** (already ordered): 1.38, 2.34, 3.02, 3.20, 3.54, 3.79, 4.21, 4.50, 4.77, 5, 5.13, 5.35, 5.55, 6.10, 6.19
3. **Step 2: Find the median (Q2):** Since there are 15 data points, median is the 8th value.
$$Q2 = 4.50$$
4. **Step 3: Find the first quartile (Q1):** Median of the lower half (first 7 values): 1.38, 2.34, 3.02, 3.20, 3.54, 3.79, 4.21
Median is the 4th value:
$$Q1 = 3.20$$
5. **Step 4: Find the third quartile (Q3):** Median of the upper half (last 7 values): 4.77, 5, 5.13, 5.35, 5.55, 6.10, 6.19
Median is the 4th value:
$$Q3 = 5.35$$
6. **Step 5: Calculate the interquartile range (IQR):**
$$IQR = Q3 - Q1 = 5.35 - 3.20 = 2.15$$
7. **Step 6: Determine the whiskers:**
- Lower whisker: smallest data point greater than or equal to $$Q1 - 1.5 \times IQR = 3.20 - 1.5 \times 2.15 = 3.20 - 3.225 = -0.025$$, so minimum is 1.38
- Upper whisker: largest data point less than or equal to $$Q3 + 1.5 \times IQR = 5.35 + 3.225 = 8.575$$, so maximum is 6.19
8. **Step 7: Construct the box plot:**
- Box from $$Q1 = 3.20$$ to $$Q3 = 5.35$$
- Median line at $$4.50$$
- Whiskers from $$1.38$$ to $$6.19$$
9. **Interpretation:**
- The median waiting time is 4.50 minutes.
- 50% of customers wait between 3.20 and 5.35 minutes.
- The waiting times are fairly spread out with an IQR of 2.15 minutes.
- No outliers are detected since all data points lie within the whiskers.
- The distribution is slightly skewed to the right as the upper whisker is longer than the lower whisker.
Final answer: Median = 4.50, Q1 = 3.20, Q3 = 5.35, Min = 1.38, Max = 6.19, IQR = 2.15, no outliers, slight right skew.
Box Plot Waiting Time 50241E
Step-by-step solutions with LaTeX - clean, fast, and student-friendly.