1. The problem states that 125 soccer players chose breakfast options: oatmeal or yogurt, with strawberries or blueberries added. 2. We are given four two-way tables (W, X, Y, Z) showing counts of players choosing each combination. 3. Clemency concluded that players who chose oatmeal tend to choose blueberries. This means the number of oatmeal-blueberries should be greater than oatmeal-strawberries. 4. Let's check each table for this condition and total players: - Table W: Oatmeal-Strawberries = 25, Oatmeal-Blueberries = 50, total = 25+50+30+20 = 125. Oatmeal-blueberries (50) > oatmeal-strawberries (25) ✔ - Table X: Oatmeal-Strawberries = 25, Oatmeal-Blueberries = 50, total = 25+50+30+25 = 130 (not 125) ✘ - Table Y: Oatmeal-Strawberries = 25, Oatmeal-Blueberries = 20, total = 25+20+30+50 = 125, but oatmeal-blueberries (20) < oatmeal-strawberries (25) ✘ - Table Z: Oatmeal-Strawberries = 50, Oatmeal-Blueberries = 25, total = 50+25+30+20 = 125, but oatmeal-blueberries (25) < oatmeal-strawberries (50) ✘ 5. Only Table W satisfies both the total number of players and the condition that oatmeal choosers tend to pick blueberries. **Final answer:** Table W is the possible representation.