1. **State the problem:** We have a data set of camera prices: 28, 44, 108, 36, 59, 71, 66. We need to find the ordered data, minimum, maximum, median, quartiles, interquartile range (IQR), and interpret the IQR. 2. **Order the data from least to greatest:** $$28, 36, 44, 59, 66, 71, 108$$ 3. **Minimum price:** The smallest value in the ordered data is $28$. 4. **Maximum price:** The largest value in the ordered data is $108$. 5. **Median price:** The median is the middle value of the ordered data. Since there are 7 values, the median is the 4th value: $$59$$ 6. **Median of the first half (first quartile, Q1):** The first half is the data below the median: $$28, 36, 44$$ The median of this subset is the middle value, which is: $$36$$ 7. **Median of the second half (third quartile, Q3):** The second half is the data above the median: $$66, 71, 108$$ The median of this subset is the middle value, which is: $$71$$ 8. **Interquartile range (IQR):** The IQR is the difference between Q3 and Q1: $$\text{IQR} = Q3 - Q1 = 71 - 36 = 35$$ 9. **Interpretation of IQR:** The IQR of 35 is relatively large compared to the data values, indicating a wide spread in the middle 50% of the data. This means the prices vary significantly among the central values. **Final answers:** - Ordered data: $28, 36, 44, 59, 66, 71, 108$ - Minimum: $28$ - Maximum: $108$ - Median: $59$ - First quartile (Q1): $36$ - Third quartile (Q3): $71$ - Interquartile range (IQR): $35$ - IQR interpretation: Relatively large, indicating a wide spread in prices.