1. The problem is to calculate the coefficient of variation (CV) given the standard deviation $s=6.21$ and the mean $\bar{x}=16.5$. 2. The formula for the coefficient of variation is: $$CV = \left(\frac{s}{\bar{x}}\right) \cdot 100$$ This formula expresses the ratio of the standard deviation to the mean as a percentage, which helps compare variability between datasets with different units or means. 3. Substitute the given values into the formula: $$CV = \left(\frac{6.21}{16.5}\right) \cdot 100$$ 4. Calculate the fraction: $$\frac{6.21}{16.5} \approx 0.3764$$ 5. Multiply by 100 to convert to percentage: $$0.3764 \cdot 100 = 37.64\%$$ 6. Therefore, the coefficient of variation is approximately $37.64\%$. This means the standard deviation is about 37.64% of the mean, indicating the relative variability of the data.