1. **State the problem:** We want to find the probability that a randomly chosen resident aged 40 or older has completed only high school or just some college.
2. **Identify the relevant data:** From the table, the age groups 40-49 and 50 & over are considered (age 40 or older).
3. **Calculate the total number of residents aged 40 or older:**
$$1672 + 5997 = 7669$$
4. **Calculate the number of residents aged 40 or older who completed only high school:**
$$331 + 760 = 1091$$
5. **Calculate the number of residents aged 40 or older who completed some college:**
$$508 + 2356 = 2864$$
6. **Calculate the total number of residents aged 40 or older who completed only high school or some college:**
$$1091 + 2864 = 3955$$
7. **Calculate the probability:**
$$P = \frac{3955}{7669}$$
8. **Simplify the fraction by canceling common factors if possible:**
$$\frac{3955}{7669}$$ (no obvious common factors to cancel)
9. **Convert to decimal and round to the nearest thousandth:**
$$\frac{3955}{7669} \approx 0.516\text{ (rounded to three decimal places)}$$
**Final answer:** The probability is approximately **0.516**.
Conditional Probability Ca7218
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