1. **Problem Statement:** Find the Mean (Direct Method), Median, and Mode of the delivery time from the given frequency distribution.
2. **Given Data:**
| Time (mins) | Frequency |
|-------------|-----------|
| 20–29 | 2 |
| 30–39 | 4 |
| 40–49 | 7 |
| 50–59 | 10 |
| 60–69 | 15 |
| 70–79 | 9 |
| 80–89 | 6 |
| 90–99 | 4 |
| 100–109 | 3 |
3. **Step 1: Calculate Midpoints ($x_i$) for each class:**
- $24.5, 34.5, 44.5, 54.5, 64.5, 74.5, 84.5, 94.5, 104.5$
4. **Step 2: Calculate $f_i x_i$ (Frequency times Midpoint):**
- $2\times24.5=49$
- $4\times34.5=138$
- $7\times44.5=311.5$
- $10\times54.5=545$
- $15\times64.5=967.5$
- $9\times74.5=670.5$
- $6\times84.5=507$
- $4\times94.5=378$
- $3\times104.5=313.5$
5. **Step 3: Calculate total frequency $N$ and sum of $f_i x_i$:**
- $N=2+4+7+10+15+9+6+4+3=60$
- $\sum f_i x_i=49+138+311.5+545+967.5+670.5+507+378+313.5=3880$
6. **Step 4: Calculate Mean using formula:**
$$\text{Mean} = \frac{\sum f_i x_i}{N} = \frac{3880}{60} = 64.67$$ minutes
7. **Step 5: Find Median Class:**
- Median position = $\frac{N}{2} = 30$
- Cumulative frequencies: 2, 6, 13, 23, 38, 47, 53, 57, 60
- Median class is where cumulative frequency first exceeds 30, which is 60–69 (cumulative 38)
8. **Step 6: Use Median formula:**
$$\text{Median} = L + \left(\frac{\frac{N}{2} - F}{f_m}\right) \times h$$
Where:
- $L=59.5$ (lower boundary of median class 60–69)
- $F=23$ (cumulative frequency before median class)
- $f_m=15$ (frequency of median class)
- $h=10$ (class width)
Calculate:
$$\text{Median} = 59.5 + \left(\frac{30 - 23}{15}\right) \times 10 = 59.5 + \frac{7}{15} \times 10 = 59.5 + 4.67 = 64.17$$ minutes
9. **Step 7: Find Mode Class:**
- Mode class is the class with highest frequency, which is 60–69 with frequency 15
10. **Step 8: Use Mode formula:**
$$\text{Mode} = L + \left(\frac{f_1 - f_0}{2f_1 - f_0 - f_2}\right) \times h$$
Where:
- $L=59.5$ (lower boundary of mode class)
- $f_1=15$ (frequency of mode class)
- $f_0=10$ (frequency before mode class)
- $f_2=9$ (frequency after mode class)
- $h=10$
Calculate:
$$\text{Mode} = 59.5 + \left(\frac{15 - 10}{2 \times 15 - 10 - 9}\right) \times 10 = 59.5 + \left(\frac{5}{30 - 19}\right) \times 10 = 59.5 + \frac{5}{11} \times 10 = 59.5 + 4.55 = 64.05$$ minutes
**Final answers:**
- Mean = 64.67 minutes
- Median = 64.17 minutes
- Mode = 64.05 minutes
Delivery Time A30A50
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