1. **Problem:** Given the marks of several students, we need to draw a frequency distribution table, calculate the Interquartile Range (IQR), and the Semi-Interquartile Range (SIQR).
2. **Step 1: Organize the data into a frequency distribution table.**
- The marks are: 79, 80, 49, 68, 70, 51, 41, 10, 18, 28, 19, 29, 30, 36, 33, 50, 43, 49, 41, 45, 47, 55, 55, 60, 50, 40, 31, 32, 10, 20, 44, 11, 21, 29, 30, 25, 26, 35, 33, 48, 42, 70, 51, 20, 26, 34, 35, 34, 67, 71.
- Group the marks into class intervals (e.g., 0-9, 10-19, 20-29, ..., 70-79, 80-89).
| Class Interval | Frequency |
|---------------|-----------|
| 0 - 9 | 0 |
| 10 - 19 | 4 (10,10,11,18,19) actually 5 |
| 20 - 29 | 7 (20,20,21,25,26,26,28,29,29) actually 9 |
| 30 - 39 | 8 (30,30,31,32,33,33,34,34,35,35,36) actually 11 |
| 40 - 49 | 9 (40,41,41,42,43,44,45,47,48,49,49) actually 11 |
| 50 - 59 | 6 (50,50,51,51,55,55) actually 6 |
| 60 - 69 | 3 (60,67,68) actually 4 (including 70?) |
| 70 - 79 | 3 (70,70,71,79) actually 4 |
| 80 - 89 | 1 (80) |
- Correct frequencies:
| Class Interval | Frequency |
|---------------|-----------|
| 0 - 9 | 0 |
| 10 - 19 | 5 |
| 20 - 29 | 9 |
| 30 - 39 | 11 |
| 40 - 49 | 11 |
| 50 - 59 | 6 |
| 60 - 69 | 4 |
| 70 - 79 | 4 |
| 80 - 89 | 1 |
3. **Step 2: Calculate the Interquartile Range (IQR).**
- Sort the data in ascending order.
- Number of data points $n=50$.
- Find $Q_1$ (25th percentile) and $Q_3$ (75th percentile).
- Position of $Q_1 = \frac{n+1}{4} = \frac{51}{4} = 12.75$th value.
- Position of $Q_3 = 3 \times \frac{n+1}{4} = 38.25$th value.
- Sorted data (first 15 values): 10,10,11,18,19,20,20,21,25,26,26,28,29,29,30
- $Q_1$ lies between 12th and 13th values: 28 and 29
- $Q_1 = 28 + 0.75 \times (29 - 28) = 28 + 0.75 = 28.75$
- Sorted data (around 38th value): 35 (36th), 36 (37th), 40 (38th), 41 (39th)
- $Q_3$ lies between 38th and 39th values: 40 and 41
- $Q_3 = 40 + 0.25 \times (41 - 40) = 40 + 0.25 = 40.25$
- Calculate IQR:
$$IQR = Q_3 - Q_1 = 40.25 - 28.75 = 11.5$$
4. **Step 3: Calculate the Semi-Interquartile Range (SIQR).**
$$SIQR = \frac{IQR}{2} = \frac{11.5}{2} = 5.75$$
**Final answers:**
- Frequency distribution table as above.
- Interquartile Range $= 11.5$
- Semi-Interquartile Range $= 5.75$
Frequency Iqr B0D97C
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