1. **Problem Statement:**
We have marks of 25 students in a class test out of 5: 40, 0.8, 4.5, 1.3, 3.5, 5, 2.5, 4.0, 2.5, 1.6, 2.0, 4.6, 3.0, 8.5, 0.9, 1.0, 2.0, 2.0, 4.5, 2.5, 3.0, 7.5, 1.5, 1.5.
We need to obtain a frequency table with discrete classes and relative frequencies.
2. **Important Note:**
The marks 40, 8.5, and 7.5 are outliers since the test is out of 5. We will exclude these outliers to create meaningful classes between 0 and 5.
3. **Step: Define discrete classes:**
We define classes as intervals: 0-1, 1-2, 2-3, 3-4, 4-5.
4. **Step: Count frequencies in each class:**
- Class 0-1: marks 0.8, 0.9, 1.0 (count 3)
- Class 1-2: marks 1.3, 1.5, 1.5, 1.6 (count 4)
- Class 2-3: marks 2.0, 2.0, 2.0, 2.5, 2.5, 2.5, 3.0, 3.0 (count 8)
- Class 3-4: marks 3.5, 4.0 (count 2)
- Class 4-5: marks 4.5, 4.5, 4.6, 5 (count 4)
5. **Step: Calculate relative frequencies:**
Relative frequency = frequency / total number of valid marks (excluding outliers).
Total valid marks = 25 - 3 (outliers 40, 8.5, 7.5) = 22.
- Class 0-1: $\frac{3}{22} \approx 0.136$
- Class 1-2: $\frac{4}{22} \approx 0.182$
- Class 2-3: $\frac{8}{22} \approx 0.364$
- Class 3-4: $\frac{2}{22} \approx 0.091$
- Class 4-5: $\frac{4}{22} \approx 0.182$
6. **Frequency Table:**
| Class | Frequency | Relative Frequency |
|-------|-----------|--------------------|
| 0-1 | 3 | 0.136 |
| 1-2 | 4 | 0.182 |
| 2-3 | 8 | 0.364 |
| 3-4 | 2 | 0.091 |
| 4-5 | 4 | 0.182 |
This table summarizes the distribution of marks in discrete classes with relative frequencies.
Frequency Table F09Bbf
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