1. **Problem statement:** Find the probability that a child picked at random has a height greater than 104cm. Given: $X=104$, $\mu=110$, $\sigma=5$ 2. **Formula:** Use the standard normal distribution formula to find the $z$-score: $$z=\frac{X-\mu}{\sigma}$$ 3. **Calculate the $z$-score:** $$z=\frac{104-110}{5}=\frac{-6}{5}=-1.2$$ 4. **Interpretation:** The probability that height is greater than 104cm is $P(X>104)=P(Z>-1.2)$. 5. **Use symmetry:** Since $P(Z>-1.2)=1-P(Z\leq -1.2)$ and from standard normal tables $P(Z\leq -1.2)=0.1151$, $$P(X>104)=1-0.1151=0.8849$$ 6. **Answer:** The probability that a child has height greater than 104cm is approximately **0.885** or 88.5%.