1. The problem is to choose the correct histogram for the given frequency table. 2. The frequency table is: | Interval | Frequency | |----------|-----------| | 0–1 | 2 | | 2–3 | 4 | | 4–5 | 3 | | 6–7 | 2 | | 8–9 | 4 | 3. A histogram represents the frequency of data intervals with bars whose heights correspond to the frequencies. 4. We compare the heights of the bars in the two histograms with the frequencies in the table: - For 0–1: frequency is 2, left histogram height is 1, right histogram height is 2. - For 2–3: frequency is 4, left histogram height is 5, right histogram height is 4. - For 4–5: frequency is 3, left histogram height is 2, right histogram height is 3. - For 6–7: frequency is 2, left histogram height is 3, right histogram height is 2. - For 8–9: frequency is 4, left histogram height is 4, right histogram height is 4. 5. The right histogram matches the frequencies exactly. 6. Therefore, the correct histogram is the right histogram with bars at 0–1, 2–3, 4–5, 6–7, 8–9 with heights 2, 4, 3, 2, 4 respectively.