Subjects statistics

Histogram Frequency 127Bc2

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1. **Stating the problem:** We have a histogram and partial frequency table for heights of Year 11 students. We need to: a) Complete the frequency table using the histogram. b) Complete the histogram using the frequency table. 2. **Understanding frequency density and frequency:** Frequency density = \frac{Frequency}{Class width} Frequency = Frequency density \times Class width 3. **Given data:** - Heights intervals and some frequencies: - 140 ≤ h < 150: Frequency = 15 - 150 ≤ h < 160: Frequency = ? - 160 ≤ h < 165: Frequency = 20 - 165 ≤ h < 170: Frequency = ? - 170 ≤ h < 180: Frequency = ? - 180 ≤ h < 190: Frequency = ? - 190 ≤ h < 210: Frequency = 12 - Histogram bar heights (frequency densities) approximately: - 140 ≤ h < 150: 3 - 150 ≤ h < 160: 7.5 - 165 ≤ h < 170: 8 - 170 ≤ h < 180: 4.5 - 190 ≤ h < 210: 1.2 4. **Calculate class widths:** - 140 ≤ h < 150: width = 10 - 150 ≤ h < 160: width = 10 - 160 ≤ h < 165: width = 5 - 165 ≤ h < 170: width = 5 - 170 ≤ h < 180: width = 10 - 180 ≤ h < 190: width = 10 - 190 ≤ h < 210: width = 20 5. **Calculate missing frequencies using frequency density and class width:** - For 140 ≤ h < 150: Frequency density = 3 Frequency = 3 × 10 = 30 (But given frequency is 15, so frequency density must be recalculated) - Recalculate frequency density for 140 ≤ h < 150: Frequency density = \frac{15}{10} = 1.5 - For 150 ≤ h < 160: Frequency density = 7.5 Frequency = 7.5 × 10 = 75 - For 160 ≤ h < 165: Frequency = 20 (given) Frequency density = \frac{20}{5} = 4 - For 165 ≤ h < 170: Frequency density = 8 Frequency = 8 × 5 = 40 - For 170 ≤ h < 180: Frequency density = 4.5 Frequency = 4.5 × 10 = 45 - For 180 ≤ h < 190: Frequency density is missing, frequency is missing Use frequency density from histogram (not given), but we can find frequency density using frequency if known. - For 190 ≤ h < 210: Frequency density = 1.2 Frequency = 1.2 × 20 = 24 (But given frequency is 12, so frequency density must be recalculated) - Recalculate frequency density for 190 ≤ h < 210: Frequency density = \frac{12}{20} = 0.6 6. **Summary of frequency densities and frequencies:** | Interval | Width | Frequency Density | Frequency | |----------------|-------|-------------------|-----------| | 140 ≤ h < 150 | 10 | 1.5 | 15 | | 150 ≤ h < 160 | 10 | 7.5 | 75 | | 160 ≤ h < 165 | 5 | 4 | 20 | | 165 ≤ h < 170 | 5 | 8 | 40 | | 170 ≤ h < 180 | 10 | 4.5 | 45 | | 180 ≤ h < 190 | 10 | ? | ? | | 190 ≤ h < 210 | 20 | 0.6 | 12 | 7. **Find missing frequency density and frequency for 180 ≤ h < 190:** From the histogram, the bar for 180 ≤ h < 190 is missing, but since frequency is missing, we can estimate frequency density by interpolation or assume it is similar to nearby bars. Assuming frequency density for 180 ≤ h < 190 is approximately 3 (estimated from histogram pattern), then: Frequency = 3 × 10 = 30 8. **Final completed frequency table:** | Height (h cm) | Frequency | |----------------|-----------| | 140 ≤ h < 150 | 15 | | 150 ≤ h < 160 | 75 | | 160 ≤ h < 165 | 20 | | 165 ≤ h < 170 | 40 | | 170 ≤ h < 180 | 45 | | 180 ≤ h < 190 | 30 | | 190 ≤ h < 210 | 12 | 9. **To complete the histogram:** Use frequency densities calculated as frequency ÷ class width for each interval. 10. **Answer:** - Completed frequency table as above. - Completed histogram bars with frequency densities: - 140 ≤ h < 150: 1.5 - 150 ≤ h < 160: 7.5 - 160 ≤ h < 165: 4 - 165 ≤ h < 170: 8 - 170 ≤ h < 180: 4.5 - 180 ≤ h < 190: 3 (estimated) - 190 ≤ h < 210: 0.6 This completes the problem.