1. **Problem statement:** (a) Identify the interval containing closest to 10 students from the histogram. (b) Determine which statement about the histogram is correct. 2. **Understanding the histogram:** - The x-axis shows height intervals: 59-62, 62-65, 65-68, 68-71, 71-74, 74-77, 77-80. - The y-axis shows frequency (number of students) with marks at 0, 10, 20. - Bar heights (frequencies) approximately: - 59-62: 3 - 62-65: 20 - 65-68: 12 - 68-71: 10 - 71-74: 10 - 74-77: 3 - 77-80: 1 3. **Answering (a):** - We look for the interval with frequency closest to 10. - Intervals 68-71 and 71-74 both have frequency 10. - Among the options, only 68-71 inches (option C) matches exactly 10 students. 4. **Answering (b):** - Option A: "Approximately half the students have heights between 65 and 71 inches." - Sum frequencies 65-68 and 68-71: 12 + 10 = 22. - Total students: 3 + 20 + 12 + 10 + 10 + 3 + 1 = 59. - Half of 59 is about 29.5, 22 is less than half, so A is false. - Option B: "The tallest person must have a height of at least 79 inches." - The last interval is 77-80 with frequency 1, so tallest person is between 77 and 80. - So tallest person could be less than 79, so B is false. - Option C: "The histogram is symmetric." - Frequencies are not symmetric around the center, so C is false. - Therefore, D: "None of the above are correct" is true. **Final answers:** (a) C. 68-71 inches. (b) D. None of the above are correct.