1. The problem asks: What percent of the time did Trent spend at least 80 minutes on homework? 2. From the data points given: 20, 40, 60, 80, 100, 120 minutes, we want to find the percentage of these times that are \textbf{at least} 80 minutes. 3. Identify the times that are \geq 80: these are 80, 100, and 120. 4. Count the total number of data points: there are 6 times in total. 5. Count the number of times \geq 80: there are 3 such times. 6. Calculate the percentage using the formula: $$\text{Percentage} = \frac{\text{Number of times } \geq 80}{\text{Total number of times}} \times 100$$ 7. Substitute the values: $$\text{Percentage} = \frac{3}{6} \times 100$$ 8. Simplify the fraction by canceling common factors: $$\frac{\cancel{3}}{\cancel{6}} = \frac{1}{2}$$ 9. Calculate the percentage: $$\frac{1}{2} \times 100 = 50$$ 10. \textbf{Answer:} Trent spent at least 80 minutes on homework \textbf{50\%} of the time.