1. **State the problem:** We want to test the claim that the proportion of Population 1 exceeds the proportion of Population 2 using two random samples. 2. **Set up the hypotheses:** - Null hypothesis ($H_0$): $p_1 \leq p_2$ (Population 1 proportion is less than or equal to Population 2 proportion) - Alternative hypothesis ($H_a$): $p_1 > p_2$ (Population 1 proportion is greater than Population 2 proportion) 3. **Sample size requirement:** - For testing proportions, each sample must have at least 5 successes and 5 failures. - Check Population 1: successes = 222, failures = 300 - 222 = 78 (both > 5) - Check Population 2: successes = 136, failures = 200 - 136 = 64 (both > 5) Thus, sample size requirements are met. 4. **Distribution and significance level:** - Use a Z-test for two population proportions. - Significance level $\alpha = 0.05$. This completes the hypothesis setup and sample size check for the test.