1. The problem is to determine which line best fits the given scatter plot points: (1,3), (2,4), (3,3), (3,4), (4,6), (5,7), (6,7), (7,9), (8,8), (9,10), (10,10). 2. To find a line of best fit, we use the linear equation formula: $$y = mx + b$$ where $m$ is the slope and $b$ is the y-intercept. 3. We estimate the slope $m$ by choosing two points roughly on the trend line. For example, from (1,3) to (10,10): $$m = \frac{10 - 3}{10 - 1} = \frac{7}{9} \approx 0.78$$ 4. Next, find the y-intercept $b$ by substituting one point into the equation: Using point (1,3): $$3 = 0.78 \times 1 + b \Rightarrow b = 3 - 0.78 = 2.22$$ 5. So the line equation approximating the data is: $$y = 0.78x + 2.22$$ 6. Comparing this to the two graph descriptions: - Top-left graph line starts near $y=2$ at $x=0$ and goes to $y=10$ at $x=10$, which matches $b \approx 2.22$ and $y(10) = 0.78 \times 10 + 2.22 = 9.99$. - Bottom-left graph line starts near $y=2$ at $x=0$ but only reaches about $y=8$ at $x=10$, which is less steep. 7. Since the calculated line fits the top-left graph description better, the top-left graph shows the line that fits the data. Final answer: The top-left graph shows the line that fits the scatter plot data best.