1. **Problem Statement:** Calculate the mean of each data set (Data A, B, C, D, E) and round the answers to two decimal places. 2. **Formula for Mean:** $$\text{Mean} = \frac{\text{Sum of all data points}}{\text{Number of data points}}$$ 3. **Calculate Mean for Data A:** Sum = 102 + 105 + 122 + 125 + 127 + 129 + 130 + 144 + 154 + 155 = 1293 Number of data points = 10 $$\text{Mean}_A = \frac{1293}{10} = 129.3$$ 4. **Calculate Mean for Data B:** Sum = 2000 + 2009 + 2011 + 2120 + 2150 + 2189 + 2220 + 2390 + 2440 + 2700 = 21229 Number of data points = 10 $$\text{Mean}_B = \frac{21229}{10} = 2122.9$$ 5. **Calculate Mean for Data C:** Sum = 21000 + 23109 + 23133 + 23190 + 24150 + 24589 + 24720 + 25390 + 25440 + 26600 = 240321 Number of data points = 10 $$\text{Mean}_C = \frac{240321}{10} = 24032.1$$ 6. **Calculate Mean for Data D:** Sum = 91000 + 103109 + 113133 + 123190 + 123150 + 124189 + 124820 + 125190 + 125440 + 126700 = 1169911 Number of data points = 10 $$\text{Mean}_D = \frac{1169911}{10} = 116991.1$$ 7. **Calculate Mean for Data E:** Sum = 391000 + 1103109 + 2113133 + 2123190 + 2423150 + 3124189 + 3524820 + 4425190 + 4825440 + 5126700 = 33304121 Number of data points = 10 $$\text{Mean}_E = \frac{33304121}{10} = 3330412.1$$ **Final answers:** - Mean Data A = 129.30 - Mean Data B = 2122.90 - Mean Data C = 24032.10 - Mean Data D = 116991.10 - Mean Data E = 3330412.10