1. **State the problem:** We are given the data set: 126, 128, 140, 124, 140, 129.
We need to find:
(a) The mean
(b) The median
(c) The mode (if any)
2. **Calculate the mean:**
The mean is the sum of all data points divided by the number of points.
$$\text{Mean} = \frac{126 + 128 + 140 + 124 + 140 + 129}{6}$$
Calculate the sum:
$$126 + 128 + 140 + 124 + 140 + 129 = 787$$
So,
$$\text{Mean} = \frac{787}{6}$$
Show cancellation step:
$$\frac{\cancel{787}}{\cancel{6}} = 131.1666... \approx 131.2$$
Rounded to the nearest tenth, the mean is **131.2**.
3. **Calculate the median:**
The median is the middle value when the data is ordered.
Order the data:
$$124, 126, 128, 129, 140, 140$$
Since there are 6 data points (even number), the median is the average of the 3rd and 4th values.
$$\text{Median} = \frac{128 + 129}{2} = \frac{257}{2}$$
Show cancellation step:
$$\frac{\cancel{257}}{\cancel{2}} = 128.5$$
So, the median is **128.5**.
4. **Calculate the mode:**
The mode is the value(s) that appear most frequently.
From the data, 140 appears twice, all others appear once.
Therefore, the mode is **140**.
**Final answers:**
- Mean = 131.2
- Median = 128.5
- Mode = 140
Mean Median Mode 56Cafd
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