1. **State the problem:** Find the mean, median, and standard deviation of the data set: 12, 15, 18, 20, 22, 25, 28.
2. **Mean:** The mean is the average of the numbers. Use the formula:
$$\text{Mean} = \frac{\sum x_i}{n}$$
where $x_i$ are the data points and $n$ is the number of data points.
Calculate the sum:
$$12 + 15 + 18 + 20 + 22 + 25 + 28 = 140$$
Number of data points $n = 7$.
Calculate the mean:
$$\text{Mean} = \frac{140}{7} = 20$$
3. **Median:** The median is the middle value when the data is ordered.
The data in order is already: 12, 15, 18, 20, 22, 25, 28.
Since $n=7$ (odd), the median is the middle value, which is the 4th value:
$$\text{Median} = 20$$
4. **Standard deviation:** Measures the spread of data around the mean.
Use the formula for sample standard deviation:
$$s = \sqrt{\frac{1}{n-1} \sum_{i=1}^n (x_i - \bar{x})^2}$$
where $\bar{x}$ is the mean.
Calculate each squared deviation:
$$(12-20)^2 = 64$$
$$(15-20)^2 = 25$$
$$(18-20)^2 = 4$$
$$(20-20)^2 = 0$$
$$(22-20)^2 = 4$$
$$(25-20)^2 = 25$$
$$(28-20)^2 = 64$$
Sum of squared deviations:
$$64 + 25 + 4 + 0 + 4 + 25 + 64 = 186$$
Divide by $n-1=6$:
$$\frac{186}{6} = 31$$
Take the square root:
$$s = \sqrt{31} \approx 5.57$$
**Final answers:**
- Mean = 20
- Median = 20
- Standard deviation $\approx 5.57$
Mean Median Stddev 3492Da
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