1. **State the problem:** We have a frequency distribution table with scores, frequency, midpoints ($m$), cumulative frequency ($c.f.$), and frequency times midpoint ($fm$). We want to analyze or find statistical measures such as the mean. 2. **Formula for mean:** The mean of grouped data is given by $$\text{Mean} = \frac{\sum fm}{\sum f}$$ where $f$ is frequency and $m$ is midpoint. 3. **Calculate total frequency ($\sum f$):** Add all frequencies: $$8 + 2 + 5 + 0 + 3 = 18$$ 4. **Calculate total $fm$ ($\sum fm$):** Add all $fm$ values: $$324 + 89 + 242.5 + 0 + 169.5 = 825$$ 5. **Calculate mean:** $$\text{Mean} = \frac{825}{18}$$ 6. **Simplify fraction:** $$\frac{\cancel{825}^{\div 3}}{\cancel{18}^{\div 3}} = \frac{275}{6}$$ 7. **Convert to decimal:** $$\frac{275}{6} \approx 45.83$$ **Final answer:** The mean score is approximately $45.83$.