1. **State the problem:** We need to find the median number of books read by students given the grouped frequency distribution. 2. **Recall the formula for median in grouped data:** $$\text{Median} = L + \left(\frac{\frac{N}{2} - F}{f}\right) \times h$$ where: - $L$ = lower boundary of the median class - $N$ = total frequency - $F$ = cumulative frequency before the median class - $f$ = frequency of the median class - $h$ = class width 3. **Calculate total frequency $N$:** $$N = 10 + 15 + 20 + 8 + 5 = 58$$ 4. **Find $\frac{N}{2}$:** $$\frac{58}{2} = 29$$ 5. **Calculate cumulative frequencies:** - Up to 0-5: 10 - Up to 5-10: 10 + 15 = 25 - Up to 10-15: 25 + 20 = 45 - Up to 15-20: 45 + 8 = 53 - Up to 20-25: 53 + 5 = 58 6. **Identify the median class:** The median class is where cumulative frequency just exceeds 29, which is the 10-15 interval (cumulative frequency 45). 7. **Assign values:** - $L = 10$ (lower boundary of median class) - $F = 25$ (cumulative frequency before median class) - $f = 20$ (frequency of median class) - $h = 5$ (class width, difference between 15 and 10) 8. **Apply the formula:** $$\text{Median} = 10 + \left(\frac{29 - 25}{20}\right) \times 5 = 10 + \left(\frac{4}{20}\right) \times 5 = 10 + 1 = 11$$ **Final answer:** The median number of books read is **11**.