1. We are given five bar charts representing results of five tests, each with three bars of different heights. 2. The problem asks: Which chart(s) have a median greater than the mean? 3. Recall the definitions: - The mean is the average of all values: $$\text{mean} = \frac{\text{sum of all values}}{\text{number of values}}$$ - The median is the middle value when the data is ordered from smallest to largest. 4. Let's analyze each chart by assigning numerical values to heights: low = 1, medium = 2, high = 3. (A) Heights: low (1), high (3), low (1) - Ordered: 1, 1, 3 - Median = middle value = 1 - Mean = (1 + 3 + 1) / 3 = 5 / 3 \approx 1.67 - Median (1) < Mean (1.67) (B) Heights: medium (2), low (1), medium (2) - Ordered: 1, 2, 2 - Median = 2 - Mean = (2 + 1 + 2) / 3 = 5 / 3 \approx 1.67 - Median (2) > Mean (1.67) (C) Heights: high (3), low (1), low (1) - Ordered: 1, 1, 3 - Median = 1 - Mean = (3 + 1 + 1) / 3 = 5 / 3 \approx 1.67 - Median (1) < Mean (1.67) (D) Heights: low (1), low (1), high (3) - Ordered: 1, 1, 3 - Median = 1 - Mean = (1 + 1 + 3) / 3 = 5 / 3 \approx 1.67 - Median (1) < Mean (1.67) (E) Heights: low (1), medium (2), medium (2) - Ordered: 1, 2, 2 - Median = 2 - Mean = (1 + 2 + 2) / 3 = 5 / 3 \approx 1.67 - Median (2) > Mean (1.67) 5. Conclusion: Diagrams (B) and (E) have median greater than mean. **Final answer:** (B) and (E)