1. **State the problem:** We have data set A with values 22, 23, 24, 25, and 26, with frequencies 6, 5, 3, 2, and 1 respectively, totaling 15 values. 2. **Find the median of data set A:** The median is the middle value when data is ordered. Since there are 15 values, the median is the 8th value. 3. **List the values in order with frequencies:** - 22 appears 6 times (positions 1 to 6) - 23 appears 5 times (positions 7 to 11) - 24 appears 3 times (positions 12 to 14) - 25 appears 2 times (positions 15 to 16) - 26 appears 1 time (position 17) 4. The 8th value falls in the 23s (positions 7 to 11), so median of A is $23$. 5. **Calculate the range of data set A:** Range = max - min = $26 - 22 = 4$. 6. **Data set B is created by adding 56 to each value in A:** - New values are 78, 79, 80, 81, 82. 7. **Median of data set B:** Adding a constant shifts all values by that constant, so median of B = median of A + 56 = $23 + 56 = 79$. 8. **Range of data set B:** Range = max - min = $(26 + 56) - (22 + 56) = 82 - 78 = 4$. 9. **Compare medians and ranges:** Median of B is greater than median of A, but ranges are equal. **Final answer:** C The median of data set B is greater than the median of data set A, and the range of data set B is equal to the range of data set A.